Roulette

Martingale roulette explained

Doubling after a loss makes the next stake grow quickly. See the arithmetic behind Martingale, including the total at risk and the effect of table limits.

Set your inputs

19/37 for a red bet on a European wheel.

Your result

$63.00

Total lost after six consecutive losses

Next stake
$64.00
Fixed-block loss chance
1.83%
Starting unit
$1.00

A progression changes exposure, not the chance of the next outcome.

Six losses from a $1 starting stake

  1. Bet 1$1$1 lost in total
  2. Bet 2$2$3 lost in total
  3. Bet 3$4$7 lost in total
  4. Bet 4$8$15 lost in total
  5. Bet 5$16$31 lost in total
  6. Bet 6$32$63 lost in total

The doubling sequence

With a $1 starting stake, the first six wagers are $1, $2, $4, $8, $16 and $32. Losing all six costs $63. The next requested wager is $64. A win at 1:1 would recover preceding losses plus one starting unit only if that next bet can actually be placed and wins.

Bankroll and maximum bets

After k losses, cumulative loss is b × (2^k − 1), and the next stake is b × 2^k. A finite bankroll or table maximum can interrupt the sequence. A string of small completed cycles does not eliminate the larger possible loss.

The probability of six losses

For a red bet on a standard European wheel, a loss has probability 19/37. Six consecutive losses in the next six spins therefore have probability (19/37)^6, about 1.83%. This is one fixed block, not the chance of ever encountering six losses.

The house edge remains

The next spin keeps the same probability regardless of stake size. Expected loss applies to each amount wagered. Doubling is not a way to turn negative expected value into a guaranteed return.